嵌固端刚度比问题

Floor No. 1 Tower No. 1 （地下一层）
Xstif= -4.6124(m) Ystif= -15.6857(m) Alf = -0.0206(Degree)
Xmass= 6.5165(m) Ymass= 3.9681(m) Gmass(活荷折减)= 8363.4844( 7685.4902)(t)
Eex = 0.4704 Eey = 0.9600
Ratx = 1.0000 Raty = 1.0000
Ratx1= 8.4933 （8.4933＞2 满足高规5.3.7条） Raty1= 17.7214
薄弱层地震剪力放大系数= 1.00
RJX1 = 4.5856E+07(kN/m) RJY1 = 7.1042E+07(kN/m) RJZ1 = 0.0000E+00(kN/m)
RJX3 = 1.4907E+07(kN/m) RJY3 = 3.1675E+07(kN/m) RJZ3 = 0.0000E+00(kN/m)
---------------------------------------------------------------------------
Floor No. 2 Tower No. 1 （地上一层）
Xstif= -0.0124(m) Ystif= 0.3905(m) Alf = 0.0000(Degree)
Xmass= 0.0302(m) Ymass= 0.1667(m) Gmass(活荷折减)= 1832.8083( 1685.3728)(t)
Eex = 0.0021 Eey = 0.0109
Ratx = 0.2222 Raty = 0.1434
Ratx1= 1.0984 （1.0984＜0.5*8.4933=4.24665；还是1.0984要小于0.5呀？（抗规6.1.14中的第二条）） Raty1= 1.1196
薄弱层地震剪力放大系数= 1.00
RJX1 = 1.0188E+07(kN/m) RJY1 = 1.0188E+07(kN/m) RJZ1 = 0.0000E+00(kN/m)
RJX3 = 1.8359E+06(kN/m) RJY3 = 1.9036E+06(kN/m) RJZ3 = 0.0000E+00(kN/m)
---------------------------------------------------------------------------
Floor No. 3 Tower No. 1（地上二层）
Xstif= -0.0483(m) Ystif= 2.9591(m) Alf = 0.0000(Degree)
Xmass= 0.1326(m) Ymass= -0.0040(m) Gmass(活荷折减)= 1608.8081( 1431.4221)(t)
Eex = 0.0087 Eey = 0.1287
Ratx = 1.1658 Raty = 1.1658
Ratx1= 1.4465 Raty1= 1.4641
薄弱层地震剪力放大系数= 1.00
RJX1 = 1.1878E+07(kN/m) RJY1 = 1.1878E+07(kN/m) RJZ1 = 0.0000E+00(kN/m)
RJX3 = 2.3878E+06(kN/m) RJY3 = 2.4290E+06(kN/m) RJZ3 = 0.0000E+00(kN/m)
---------------------------------------------------------------------------

小弟第一次做有地下室的嵌固层， 很是不明白怎样判断嵌固的问题，对抗规6.1.14中的第2条不理解，在这里请教各位前辈指点，我的这个计算结果满足要求吗？不满足该怎么调整？算嵌固端是不是可以不考位移角限值和位移比的问题呀？万分感谢！！！