如何在ansys中判断平动系数与扭转系数之比

对一高层框筒结构做模态分析时,对以下输出窗口不太理解,在pkpm容易得到平动系数与扭转系数之比,在ansys中如何实现?以下为输出窗口:

***** PARTICIPATION FACTOR CALCULATION ***** X DIRECTION

CUMULATIVE
MODE FREQUENCY PERIOD PARTIC.FACTOR RATIO EFFECTIVE MAS
S MASS FRACTION

1 0.429296 2.3294 -0.40567E-04 0.000000 0.164566E-0
8 0.797782E-16
2 0.436928 2.2887 3827.3 1.000000 0.146481E+0
8 0.710111
3 0.485836 2.0583 -0.54042E-04 0.000000 0.292056E-0
8 0.710111
4 1.20699 0.82851 -0.68919E-02 0.000002 0.474976E-0
4 0.710111
5 1.59381 0.62743 -0.16420E-04 0.000000 0.269631E-0
9 0.710111
6 1.86664 0.53572 -0.77363E-02 0.000002 0.598502E-0
4 0.710111
7 1.90108 0.52602 -2012.6 0.525866 0.405071E+0
7 0.906481
8 1.91113 0.52325 -0.83127E-02 0.000002 0.691018E-0
4 0.906481
9 2.24817 0.44481 0.17173E-01 0.000004 0.294911E-0
3 0.906481
10 2.56085 0.39049 0.20173E-02 0.000001 0.406945E-0
5 0.906481
11 3.31979 0.30122 0.27363E-02 0.000001 0.748739E-0
5 0.906481
12 4.14477 0.24127 -0.86123E-02 0.000002 0.741716E-0
4 0.906481
13 4.39289 0.22764 1385.1 0.361910 0.191859E+0
7 0.999491
14 4.39403 0.22758 0.10522E-01 0.000003 0.110718E-0
3 0.999491
15 4.40970 0.22677 0.27355E-01 0.000007 0.748294E-0
3 0.999491
16 4.43549 0.22545 -0.23621E-01 0.000006 0.557958E-0
3 0.999491
17 4.47178 0.22362 0.10350E-01 0.000003 0.107130E-0
3 0.999491
18 4.61076 0.21688 102.50 0.026780 10505.3
1.00000
19 4.96660 0.20134 0.23888E-01 0.000006 0.570658E-0
3 1.00000
20 5.09249 0.19637 0.10155E-01 0.000003 0.103128E-0
3 1.00000
SUM OF EFFECTIVE MASSES= 0.206279E+0