发布于:2006-01-26 00:27:26
来自:建筑结构/混凝土结构
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在偏心竖向力作用下
Qik = (Fk + Gk) / n ± Mxk * Yi / ∑Yi ^ 2 ± Myk * Xi / ∑Xi ^ 2
(基础规范 8.5.3-2)
Q1k = (Fk + Gk) / n + Mxk * Yi / ∑Yi ^ 2 - Myk * Xi / ∑Xi ^ 2
= 161.7+(800*0.85)/(4*0.85^2)-(0*0.85)/(4*0.85^2)
= 397.0kN ≤ 1.2Ra = 480kN
Q2k = (Fk + Gk) / n + Mxk * Yi / ∑Yi ^ 2 + Myk * Xi / ∑Xi ^ 2
= 161.7+(800*0.85)/(4*0.85^2)+(0*0.85)/(4*0.85^2)
= 397.0kN ≤ 1.2Ra = 480kN
Q3k = (Fk + Gk) / n = 161.7kN
Q4k = (Fk + Gk) / n - Mxk * Yi / ∑Yi ^ 2 - Myk * Xi / ∑Xi ^ 2
= 161.7-(800*0.85)/(4*0.85^2)-(0*0.85)/(4*0.85^2)
= -73.6kN ≤ 1.2Ra = 480kN
Q5k = (Fk + Gk) / n - Mxk * Yi / ∑Yi ^ 2 + Myk * Xi / ∑Xi ^ 2
= 161.7-(800*0.85)/(4*0.85^2)+(0*0.85)/(4*0.85^2)
= -73.6kN ≤ 1.2Ra = 480kN
此上的结构中Q4k Q5k出现负值可以吗,会不会使桩与承台拉裂开呀!请指教
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