请教：嵌固端如何确定

四层框架，地下一层。
地下室为混凝土外墙，
我按地下室层数为0 和 土层水平抗侧力系数的比例系数为0 分别计算。
地上一层与地下室侧移刚度比值为0.08左右，此时我把基础当做嵌固端合适么？
如果地下一层为嵌固端还需要满足 抗规6.1.14条吧？


结果如下：
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各层刚心、偏心率、相邻层侧移刚度比等计算信息
Floor No : 层号
Tower No : 塔号
Xstif，Ystif : 刚心的 X，Y 坐标值
Alf : 层刚性主轴的方向
Xmass，Ymass : 质心的 X，Y 坐标值
Gmass : 总质量
Eex，Eey : X，Y 方向的偏心率
Ratx，Raty : X，Y 方向本层塔侧移刚度与下一层相应塔侧移刚度的比值
Ratx1，Raty1 : X，Y 方向本层塔侧移刚度与上一层相应塔侧移刚度70%的比值
或上三层平均侧移刚度80%的比值中之较小者
RJX，RJY，RJZ: 结构总体坐标系中塔的侧移刚度和扭转刚度
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Floor No. 1 Tower No. 1
Xstif= 35.3724(m) Ystif= -27.3659(m) Alf = -41.7618(Degree)
Xmass= 35.3600(m) Ymass= -21.2758(m) Gmass= 4947.3350(t)
Eex = 0.0004 Eey = 0.1876
Ratx = 1.0000 Raty = 1.0000
Ratx1= 14.9688 Raty1= 14.5265 薄弱层地震剪力放大系数= 1.00
RJX = 1.0146E+08(kN/m) RJY = 1.0325E+08(kN/m) RJZ = 1.0880E+11(kN/m)
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Floor No. 2 Tower No. 1
Xstif= 36.1757(m) Ystif= -24.5983(m) Alf = 9.6388(Degree)
Xmass= 35.7219(m) Ymass= -21.3114(m) Gmass= 4095.0737(t)
Eex = 0.0273 Eey = 0.2022
Ratx = 0.0846 Raty = 0.0872
Ratx1= 1.2845 Raty1= 1.2828 薄弱层地震剪力放大系数= 1.00
RJX = 8.5875E+06(kN/m) RJY = 8.9995E+06(kN/m) RJZ = 2.3779E+09(kN/m)
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Floor No. 3 Tower No. 1
Xstif= 36.1438(m) Ystif= -24.5825(m) Alf = 9.4668(Degree)
Xmass= 35.8340(m) Ymass= -21.6028(m) Gmass= 3630.4785(t)
Eex = 0.0186 Eey = 0.1834
Ratx = 1.0000 Raty = 1.0000
Ratx1= 1.3024 Raty1= 1.2999 薄弱层地震剪力放大系数= 1.00
RJX = 8.5875E+06(kN/m) RJY = 8.9995E+06(kN/m) RJZ = 2.3745E+09(kN/m)
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Floor No. 4 Tower No. 1
Xstif= 36.3511(m) Ystif= -24.6895(m) Alf = 9.4668(Degree)
Xmass= 36.8185(m) Ymass= -21.9605(m) Gmass= 3180.0989(t)
Eex = 0.0276 Eey = 0.1650
Ratx = 0.9598 Raty = 0.9616
Ratx1= 1.2500 Raty1= 1.2500 薄弱层地震剪力放大系数= 1.00
RJX = 8.2419E+06(kN/m) RJY = 8.6539E+06(kN/m) RJZ = 2.3664E+09(kN/m)
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Floor No. 5 Tower No. 1
Xstif= 36.3511(m) Ystif= -24.6895(m) Alf = 9.4668(Degree)
Xmass= 35.1572(m) Ymass= -21.4475(m) Gmass= 2828.2148(t)
Eex = 0.0705 Eey = 0.1961
Ratx = 1.0000 Raty = 1.0000
Ratx1= 1.2500 Raty1= 1.2500 薄弱层地震剪力放大系数= 1.00
RJX = 8.2419E+06(kN/m) RJY = 8.6539E+06(kN/m) RJZ = 2.3664E+09(kN/m)
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