发布于：2009-11-18 20:38:18
来自：建筑结构/钢结构工程
[复制转发]
近日在复习钢结构时，在钢结构螺栓连接部分遇到了疑惑
下面是螺栓连接偏心受剪的公式
N1t=A1*剪应力=A1*T*r1/Ip=A1*T*r1/[A1*（r1^2+r2^2+…………）]
=T*r1/(r1^2+r2^2+…………)
A1:为1个螺栓的截面积
Ip：螺栓群截面对形心轴的 极惯性矩
r1，r2。。。。：为任一螺栓致形心的距离
公式里面，Ip如何转化为 A1*（r1^2+r2^2+…………），我自己的推导如下
Ip=Ix+Iy
Ix=Ix0+(a^2)*A
Iy=Iy0+(b^2)*A 惯性矩移轴公式
a^2+b^2=r^2
这样得到
Ip=Ix0+Iy0+(r^2)*A
与前面的公式就不一样了
我想了很久也没有想通，希望各位能够指点
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